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## What’s New In Photoshop 2021 (version 22)?

Q: Show that $\sin(\frac{3\pi}{5}) + \sin(\frac{\pi}{5}) + \sin(\frac{2\pi}{5}) = -\sin(\frac{7\pi}{5})$ Show that $$\sin\left(\frac{3\pi}{5}\right) + \sin\left(\frac{\pi}{5}\right) + \sin\left(\frac{2\pi}{5}\right) = -\sin\left(\frac{7\pi}{5}\right)$$ My idea: \begin{align} \sin\left(\frac{3\pi}{5}\right) + \sin\left(\frac{\pi}{5}\right) + \sin\left(\frac{2\pi}{5}\right) & = \sin\left(\frac{\pi+3\pi}{5}\right) + \sin\left(\frac{\pi+\pi}{5}\right) + \sin\left(\frac{\pi+2\pi}{5}\right) \\ & = \sin\left(\frac{\pi+4\pi}{5}\right) + \sin\left(\frac{\pi+2\pi}{5}\right) \\ & = \sin\left(\frac{2\pi+4\pi}{5}\right) + \sin\left(\frac{\pi+2\pi}{5}\right) \\ & = \sin\left(\frac{7\pi}{5}\right) \end{align} My solution doesn’t really work but I don’t think my work should be that bad. Can anyone help me see what is going wrong? Thank you in advance! A: The idea is right. Here you should use $$\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b)$$ // Copyright 2013 The Go Authors. All rights reserved. // Use of this source code is governed by a BSD-style // license that can be found in the LICENSE file. // +build go1.7 package ssa // This file defines instruction types for the Inst simple instruction // format.

## System Requirements:

Windows Vista or higher 1GHz processor 512MB RAM 1024×768 display Supported OS’s Windows Vista/7/8/10 MAC OS X 10.6 Snow Leopard Linux 2.6.19 or later Mandatory Extras 20-40GB Hard Drive 8-40GB Flash Drive Minimum 1024×768 Resolution Drivers: DSF5101 DSF5110 DSF5113 DSF5122 DSF5221